Three non-concentric circles of equal radii are drawn such that each circle touches the other two externally. The centres are joined to form a triangle whose area is 17320.5 cm^2. Find the area of the triangle not included in the circles.

0 votes

5236.6 sq cm. If the radius of each circle is a, the equilateral triangle has base 2a and height 1.73205 a giving the area equal to 1.732.5 a*a and equating this to 17320.5 gives a=100 cm. Since the angles of the triangle are 60 degrees, in each case the area of the triangle not included in the circle is 1/6th the area of the circle of 360 degrees. Each case this comes to one sixth of 3.142*100^2 that is 5236.6 sq cm

...